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Mathematics 20 Online
OpenStudy (anonymous):

cosine rule : cos(a)=-1/sqrt(2).. how do i evaluate this ? can a = 3/4pi and 5/4pi ?

OpenStudy (lgbasallote):

have you tried taking the arc cosine of both sides?

OpenStudy (anonymous):

yes...

OpenStudy (lgbasallote):

or are you supposed to use fancy complicated trigonometric formulas?

OpenStudy (anonymous):

3/4pi and 5/4pi both answers?

OpenStudy (anonymous):

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OpenStudy (anonymous):

yes...do u know this?

OpenStudy (anonymous):

YES

OpenStudy (anonymous):

how can an angle in triangle = 5/4pi ?

OpenStudy (anonymous):

see in 2nd and 3rd quadrant cos will be negative....and you have not been asked for a triangle

OpenStudy (anonymous):

no i was using the cosine rule to find angle ..

OpenStudy (anonymous):

sorry my bad.. i was finding angle in triangle using cosine rule and got what istated in queston

OpenStudy (anonymous):

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OpenStudy (anonymous):

and u r aware with the identities cos(pi-theta) = -cos(theta) cos(pi+theta) = - cos(theta)

OpenStudy (anonymous):

YES i solved it already .. 3pi/4 and 5pi/4

OpenStudy (anonymous):

good...:) then u know...how to solve this type of question?

OpenStudy (anonymous):

im not asking how to solve sine equations.. just when using cosine rule to find angle in a triangle as i did.. are both 3pi/4 and 5pi/4 possible angles ? for say alpha

OpenStudy (anonymous):

okay so it was originally \[(\sqrt{10})^{2} = (\sqrt{2})^{2} + 2^2 -2(2)(\sqrt{2})\cos(x) \] which simplified to \[\cos(x)=-\frac{1}{\sqrt{2}} \]

OpenStudy (anonymous):

oh ok...then rule out that angle...it can't be....sorry

OpenStudy (anonymous):

so x=3pi/4,5pi/4 but angles in triangle<pi .: 5pi/4 not soln?

OpenStudy (anonymous):

yes...u r right

OpenStudy (anonymous):

if u r being asked in a triangle then x=3 pi/4

OpenStudy (anonymous):

hm ok..

OpenStudy (anonymous):

and uh.. how to solve tan equations? like tan(x)=-1 not quite sure

OpenStudy (anonymous):

use the identity tan(pi - theta) = -tan(theta)

OpenStudy (anonymous):

do i get x=3pi/4 and 7pi/4 and keep adding 2pi to each one ?

OpenStudy (anonymous):

or tan( 2 pi -theta) = -tan(theta)

OpenStudy (anonymous):

yes...actually when tan theta= x then x= n(pi) + theta, where n = ....-1,-2,-1,0,1,2,3....

OpenStudy (anonymous):

yeah im just wondeirng do u keep adding pi or get the 2 angles and add 2 pi.. or same thing

OpenStudy (anonymous):

aksh??

OpenStudy (anonymous):

actually tan has a period pi....

OpenStudy (anonymous):

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