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Mathematics 13 Online
OpenStudy (anonymous):

80y

OpenStudy (anonymous):

well that looks like an absolute value graph. So you start with y = \[\left| x \right|\]

OpenStudy (anonymous):

it shifted to the right 5 units

OpenStudy (anonymous):

and up 5 units

OpenStudy (anonymous):

y=\[\left| x-5 \right|+5\]

OpenStudy (anonymous):

It looks like it's only shifted up by 2, but the axes aren't labeled, so maybe I'm just missing the measurement scale.

OpenStudy (anonymous):

oh sorry. yes

OpenStudy (anonymous):

it shifted 2

OpenStudy (anonymous):

so y=\[\left| x-5 \right|+2\]

OpenStudy (anonymous):

Also, it looks pretty thin, so maybe a multiplier outside?

OpenStudy (anonymous):

I can't really tell base on the graph

OpenStudy (anonymous):

based*

OpenStudy (anonymous):

is that one point, (4,5)?

OpenStudy (anonymous):

(4,4)?

OpenStudy (anonymous):

ok, so there's a multiplier on the outside

OpenStudy (anonymous):

I think it's 2

OpenStudy (anonymous):

so y=\[2\left| x-5 \right|+2\]

OpenStudy (anonymous):

if you plugged 4 in, you would get 2(1)+2 = 4 :)

OpenStudy (anonymous):

haha oh dear, ok

OpenStudy (anonymous):

which one is the correct graph?

OpenStudy (anonymous):

Can check by plugging in points to the equation and see if they match up with the picture.

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