Question

What is the magnitude of the speed of a person at the equator due to rotational speed of the Earth?

Answer 1

Firstly calculate the angular speed of rotation of earth:
\[\omega=\frac{2\pi}{T}=\frac{2\pi}{24\times 60\times 60}=\frac{\pi}{43200}\]Now, velocity at equator can be obtained by simply using the relation,
V=R\(\omega\)
where R is radius of earth
So, \[V=6400000\times\frac{\pi}{43200}=465.42ms^{-1}\]

Answer 2

can you write out this math work using the draw function.. my computer isn't putting it into the equation.. its all jumbled.

Answer 3

Keep pressing F5

Answer 4

? it did nothing?

Answer 5

see this! Its a screenshot!

Answer 6

thanks! :)

Answer 7

Welcome!