Question

When sodium is excited in a flame, two ultraviolet spectral lines at (wave length symbol)=372.1 nm and (wave length symbol)=376.4 nm respectively are emitted. Which wavelength represents photons with

a) high energy?
b) longer wavelengths?
c) higher frequencies?

Answer 1

ok so you just use:
E=h*f
and
c=f*lambda
where f = frequency and lambda is wavelenght...
it is well known fact that lower wavelenght have higher energy but ill leave it for you to calculate it...