Question

How would you factor this: (r+1)^2 + 8t(r+1) + 16t^2

Answer 1

Quadratic form. Make a substitution, x=(r+1) then factor as normal for a quadratic trinomial.

Answer 2

Here's a hint: 4t*4t = ? 4t+4t = ?

Answer 3

4t * 4t would give you 8t^2 where as the other would give you 8t? So x^2 +8tx? but then you're stuck with 16t^2

Answer 4

Close.

Answer 5

You want to get it in the form (x+a)(x+b)

Answer 6

(x+a)(x+b) = x^2 + ax + bx +ab

Answer 7

In your case, ax+bx = 8tx, x=(r+1), and ab = 16t^2

Answer 8

ya but in this case b and a are a constant, here with x replacing r+1 im still stuck with 2 unknown. :/

Answer 9

So i end up doing this : x^2 +8tx + 16t^2 which then gives me (x+4t)(x+4t) do i then just plug in r + 1?

Answer 10

Thank you I did get it! However not to sure if i do understand but thanks nonetheless