The radius of a molybdenum atom is 136 pm. How many molybdenum atoms would have to be laid side by side to span a distance of 1.11 mm?

Question

pfenn1 · Answer

How many pm are there in a mm?

anonymous · Answer

1000? i think

pfenn1 · Answer

I just looked it up and it looks like $$1  mm = 10^{9}  {  picometers}$$

pfenn1 · Answer

So how many picometers in 1.11 mm?

anonymous · Answer

0.00000111 or 1.11E-6

pfenn1 · Answer

1.11 mm = 1.11 x 10^9 pm.  So to figure how many molybdenum atoms would have to be laid side by side to span a distance of 1.11 x 10^9 pm, what would you do?

anonymous · Answer

i have a pellet calc. idk

anonymous · Answer

times it by 136?

pfenn1 · Answer

Lets say you have a distance x, and you want to find how many objects of width y would fit, you would divide x by y. Like how many 1 inch thimbles would fit into a box 4 inches long?  Four, right?  So here you would divide the total distance of 1.11 x 10^9 pm by the diameter of the molybdenum atom, which is twice the radius of 136 pm.

pfenn1 · Answer

Does this make any sense to you?

anonymous · Answer

ya , i undr stand it now. thank you.

pfenn1 · Answer

You are welcome.