What is the limit of abs(x-2)/(x-2) as x approaches 2?
use one-sided limits
abs(x-2)/(x-2) means just the absolute value of (x-2) divided by (x-2).
\[ \large \lim_{x\to2}\frac{|x-2|}{x-2} \] right?
Exactly
compute separatedly \[ \Large \lim_{x\to2+}\frac{|x-2|}{x-2} \] and \[ \Large \lim_{x\to2-}\frac{|x-2|}{x-2} \] (one-sided limits)
Alright, I understand the graphical process of one-sided limits, but is there an analytical (algebraic) approach?
just follow this: \[ \Large x\to2+\Rightarrow x>2\Rightarrow x-2>0\Rightarrow |x-2|=x-2 \]
you could change the abs value to x-2 for x>2 2-x for x<2 take limit of each case
Does the limit here actually exist? Since the limit from the left isn't equal to the limit from the right.
no it does not
So would the answer be "does not exist b/c..." or the two different values it approaches from either side?
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