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simplify 9x^(2/3)/3x^(1/6)
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Use this \(\huge \frac{x^a}{x^b}=x^{a-b}\)
and as u know 9/3 will be 3.
unless....
unless the question actually is, (9x^(2/3)/3)x^(1/6)
\[9x ^{2/3}\div 3x ^{1/6}\]
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its 3x^(1/2)...as power of x are subtracted 2/3 - 1/6.
so what u got as \(\huge \frac{x^{2/3}}{x^1/6}=x^{2/3-1/6}=?\)
so I subtract as I normally would for fractions?
yup, what will be 2/3-1/6 ?
4/6-1/6=3/6=1/2. I See now.
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thanks to everybody that posted a response.
welcome :)
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