Question

Assume that 6 people, including
the husband and wife pair, apply for 5 sales positions. People are hired at random. What is the probability that one is hired and one is not?

Answer 1

its been a while since ive done stats. so please forgive me if this turns out badly lol

Answer 2

anything helps!

Answer 3

Lets assume that we have 2 groups. one group will contain the husband and wife. The other will contain the other 4 people

Answer 4

in order for BOTH the husband and the wife to be hired, we must choose 2 from their group, and we must fill the other 3 slots with the other group.

Answer 5

that is, the probability of them BOTH getting a job is
\[((2c2) * (4c3))/(6c5)\]

Answer 6

now, whatever that value is, if you subtract from 1 you should have the answer, or at least i hope

Answer 7

however, this approach will NOT work if there is a chance for NIEHTER of them to get hired. this one works becuase there are 2 states. both hired, or only one hired. you would need to make another equation if there is a chance that niether of them get hired

Answer 8

thank you so much! that worked. :D