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At (pi,0), y' =cos(sinx)cos(x)
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hello
Integrate both sides You may want to use a substitution.
im trying to find the tangent line
equation that is
Oh.
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my book has them plugging in pi for the trig functions
So you are already given the general form of the slope and lines have this form y=mx+b So evaluate y' at x=pi and that is m To find the y-intercept b, you use the point (pi,0) where x=pi and y=0 and plug it into y=mx+b to find b
yes thats my problem, somehow my book is getting -1 and i am not sure how
cos(pi) = 1
cos(pi)=-1
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? how
ohhhh im thinking 90
at 180 x = -1
gotcha
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