Question

Did I do this first step in finding the derivative of the function at x=0 right?
y= x^2 - 3x - 1

(x-h)^2 - 3(x-h) - 1 - x^2 - 3x -1

Answer 1

Oops, forgot to add one thing. All that is over H.

Answer 2

you need to be careful with the signs:

( (x-h)^2 - 3(x-h) - 1 - (x^2 - 3x -1) ) / h

Answer 3

note that:

- (x^2 - 3x -1) != - x^2 - 3x -1

Answer 4

Oh that makes sense, so it would be
( (x-h)^2 - 3(x-h) - 1 - x^2 + 3x +1) ) / h

Thanks for getting me started!

Answer 5

thats it! and you are more than welcome my friend! :)