Question

anyone want to help me please?
What are the ordered pairs?
Using the process of elimination method.
5u +3v = -18
2u + v = -8

Answer 1

multiply the second equation by 3 all the way across and subtract it from the first equation

Answer 2

or if you prefer multiply the second equation by \(-3\) and add. here are the steps

Answer 3

\[5u+3v=-18\]
\[-6u-3v=24\] now add in a column, get
\[-u=6\] and so \(u=-6\)

Answer 4

I get that part but I am confused on how to find the ordered pairs?

Answer 5

oh now that you have \(u=-6\) you can find \(v\) by substituting \(-6\) for \(u\) in either equation

Answer 6

\[2u + v = -8
\]
\[2(-6)+v=-8\]
\[-12+v=-8\]
\[v=4\]

Answer 7

so my ordered pairs are (-6,4) ?

Answer 8

so the "ordered pair" is \((-6,4)\)

Answer 9

yes

Answer 10

thank you i am glad you showed the ''steps'' as well. so that I understand. :)

Answer 11

yw