how do you solve for cubed factoring example 8y^3-27x^3

Question

anonymous · Answer

Just cube root the whole function.
$$\sqrt[3]{8y-27x}$$
Then simpify 8 and 27 by taking the cube root of that too. Got it?

anonymous · Answer

$a^3-b^2=(a-b)(a^2+ab+b^2)$ with $a=2y,b=3x$ in other words you are supposed to recognize both terms as perfect cubes

anonymous · Answer

sorry to say you cannot "cube root" the whole thing. your job is to factor. hope it is clear

anonymous · Answer

oh except i made a typo, it should be 
$$a^3-b^3=(a-b)(a^2+ab+b^2)$$

anonymous · Answer

Well you pretty much get the same exact answer because they are perfect cubes.

anonymous · Answer

thanks so much this will help for tomorrows quiz !!

anonymous · Answer

not to be picky, but they are not at all the same thing
asking to factor is not the same as asking to take the cube root.

anonymous · Answer

But wouldn't the formula you wrote one that could be used to factor out a cubed root ?