Graph the following inequality. 4x – y > 8 _
Solve the inequality for y as in the form y < (some expression in x). Since this is an inequality and not a "less than or equal to", the start of the graph will be a dotted line (ie., not part of the solution) but instead, the dotted line will serve to distinguish one "part" of the graph area from the rest of the graph. Simply choose a y value that is above or below the dotted line and see if that y value satisfies the inequality. If not choose the other side of the graph. Shade the appropriate chosen side. Then you're done.
I am a beginner in algebra and do not even know where to begin on this, could you show me?
No problem. First, start with easiest and first part, the inequality. Solve it for y by isolating y on one side and the rest on the other. By convention, you'll want to put the y on the left side. Make a dotted line out of it by setting x to 0 and then solve for y. Now you've got one point for the dotted line. You'll need a second point before drawing the dotted line. Then set y to 0 so that you can solve for x. Now you've got your second point for the line. Are you with me up to this point?
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