Use the method of substitution to solve the system of linear equations
8x+4y=8/5
y=5x-1

Question

Use the method of substitution to solve the system of linear equations
8x+4y=8/5
y=5x-1

anonymous · Answer

plug in the value of Y into the equation, 
8x+4y=8/5 instead of 4y you would put in the value of Y like this: 8x+4(5x-1)=8/5 then just solve(: do you get that or you need more help?

anonymous · Answer

Substitution means you can plug in one value of y for another. they made it easy for you by singling out the y, by y=5x-1
Plug y=5x-1 into the other equation, 8x+4(5x-1)=8/5. From there you can single out the value of x, and plug x back in to get y.

anonymous · Answer

okay what i have so far is 28x=9/5 is that right so far?

anonymous · Answer

I don't understand how you got 28x=9/5

You should make sure to factor out correctly. 4(5x-1)= 20x-4. 20x-4+8x= 28x-4=8/5. 28x= 8/5 +4. From there it should be easy to get the x. After getting x, plug into the original equations(hint, pick the easier one) and voila you got y.

anonymous · Answer

does x =1?

anonymous · Answer

oops i messed that up i think

anonymous · Answer

okay so 28x=8/5+4. so do i combine 8/5 and 4?