Two players kick a soccer ball at the same time. If one player applies a force of 100N (N 25 degrees W ) and the 250g ball experiences an acceleration of 200m/s^2 (W 15 degrees S), determine the magnitude and direction of the force applied by the second player.
I just wanna know the algorithm of this problem. If i can't solve it, i'll ask for the mathematical steps to get the answer.
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Find the components of F1 and a x component of F1/m + x component of F2/m = x component of a y component of F1/m + y component of F2/m = y component of a
remember to convert 250 g to kg before you start
can't you just convert a to F2 using the mass in kg So F2 = ma F2 = 50N Would that get the same answer?
direction?
direction?
"determine the magnitude and direction of the force"
Also, your way, whatever it is, totally neglects the 100N force..
Wait, so you have to divide each vector by the mass?
And no that was just the gist of my way. I actually converted the acceleration to force using the mass Then find the resultant now that both the vectors are the same unit
if you don't want to divide by mass, you don't have to... totally fine to solve it as x component of F1 + x component of F2 = x component of m*a y component of F1 + y component of F2 = y component of m*a
your choice:)
I am reallylost. :P
ask a question or something, this is pretty straight forward, so I don't know where you're getting lost...
can you do that and tell me what you get, I have the answers so I can see if your ways is correct. Just do it on paper since I know what you're talking about. And since it's much faster
F/m is an acceleration ... do you agree? so the x component of F1/m (the acceleration caused by Force 1) PLUS the x component of F2/m (the acceleration caused by Force 2) must equal the net x acceleration.... (which we are given)
Welps, I didn't do the question right. I understand what you're saying :D Thanks, you have a new fan:)
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