Help on this please... The recommended weight range for someone who is 62'' tall is ( ) to ( ). See Attachment
Since there are two values, I'm guessing one way to do it would be to plug 62 instead of h although I am not sure.
yes, I believe they want to plug 62 for h.
I got from 107 to 140
that is Correct! thanks! Just so you know that I am doing the work and not just copying what you say.... I did attempt it...here is my first equation.. 25h-7w=800 25(62)-7w=800 1550-7w=800 -7w=825 w=118 So I did something wrong... because you got 107.
800-1550 =-750 not 825
ah ha! I was going by the example they gave me. Thank you!
Do you know if the answer was right?
Yes. Soon as I enter them I am allowed to ''check'' my answer. And you were correct! :) (as usual) LOL
Ahh, great.
but at least you are a good teacher and I am LEARNING. :)
I have one more graphing question then I will be done for tonight. Do you have time to help me? (I can't wait til graphs are done!) LOL
Sure, no problem.
Graph the system of linear inequalities. 4x-2y < 0 2x+4y <8
but both those have the line under them.
Ok so what do you know about the lines already. Are they dotted or solid?
dotted. (i think).. hope LOL
If they have the little bar under, it means they are solid. Remember that. A bar under means that the line is SOLID!
:(
Haha, Now can you isolate both y's?
Ok, remembering that!!! bar under means SOLID! got it!
Great! :)
Isolate the first equation first. Leave the other one out for now.
well, you're gonna kill me LOL I jumped ahead and tried to do it and got it wrong.. So I have to attempt to get a similar one correct. Which they gave me 4x-6y < 0 6x +4y < 24
Ok... New one then! So... let's work with the first equation ONLY for now so is there any lines under those?
both yes
Ok!
Solid!
:)
\[4x-6y \le0\] Substract 4x from both sides. \[-6y \le-4x\] Make them both positive so SIGN SWITCHES! \[6y \ge4x\] Divide both sides by 6! \[y \ge 2/3x\] I reduced 4/6 to 2/3 for the x
Try to find two coordinates for \[y \ge2/3x\] now if you can.
Oh wow... no wonder I got the first one wrong, lol
These are easy to do once you understand them.
Ok, I am waiting for the ''easy'' part to come along haha. so i better get understanding them, lol
Did you find two pairs of coordinates for the equation?
no because the fraction is confusing me.
Ok so we'll do it easy with fractions with a TABLE OF VALUES :D
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You have 3 pairs of coordinates on here which is more than enough to create a line.
As you can see, you just plug in the numbers!
Now let's graph the first line into our cartesian plane!
(0,0), (3,2) (6,4)
Exactly.
am I headed in the right direction lol OK!
Yes, you are.
Your first line should look like this!
Now we need to do the same thing with the second equation and add it to the cartesian plane.
my first line was same as yours...working on my second line.
Great! Start by isolating your y again.
\[6x + 4y \le24\]
divide both sides by 6?
By 4 since it's the y you want to isolate.
y > 1/5x ?
What happened to your 24?
The x is right although it's negative.
24 when divided by 4 is 6
Yes so you add it also.
Now you mixed up the signs also.
I'll explain this in detail. Look.
Just when I thought the last problems were starting to make sense LOL
OK go ahead.
\[6x + 4y \le24\] TRY TO GET Y BY ITSELF! If you have 6x on the left, you must get rid of it. Remember this!!!!!!! What you do to one side, you must do to the other!!! 6x-6x + 4y < or equal to 24-6x This now makes 4y < or equal to 24-6x Divide everything by 4 because....What you do to one side, you do to the other! \[y \le6-1.5x\]
Ah! and now to figure out what the coordinates are
Try with a table of values .
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