Question

solve the equation: 5x^3=5x(x+12)

Answer 1

the farthest i got was up to this step
5x^2+ 60x-5x^3

Answer 2

=0

Answer 3

Well aperntly x=0 is a solution if not devide by x and you get a quadratic equation.

Answer 4

5x^2+60x-5x^3=0

Answer 5

5x^3=5x(x+12)

= 5x^2 = 5x + 60

x^2 - x - 12 =0

Answer 6

ok so from 5x^3=5x(x+12)
then you move the 5x^3
so you get 5x(x+12)-5x^3=0
so now you distribute the 5x
that gives you 5x^2 +60x-5x^3=0

Answer 7

I believe this answer is going to have 3 solutions.

Answer 8

right because of the x^3

Answer 9

-5x^2 +5x +60 = 0
to find the last two roots.

Answer 10

factorable.

Answer 11

Do you understand how to do that now @Mberdeja501 ?

Answer 12

what where did the - come from? @Algebraic! ?

Answer 13

from
x(-5x^2 +5x +60) =0

Answer 14

When I worked it I came out with solutions of 0,-3,4. Is that what you got also?

Answer 15

yes

Answer 16

Great!!

Answer 17

factorable how? im lost :( haha @Algebraic!

Answer 18

(-5x +20)(x+3)

Answer 19

have you got the answer or need further assistance?

Answer 20

Let me know what I need to go over again.. I will be more than glad to. :)

Answer 21

oops ok i get it now. thanks

Answer 22

No problem @Mberdeja501!! Glad I could help you!!