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Mathematics 21 Online
OpenStudy (anonymous):

Determine if the subset of R \[ M := \{\frac{n-1}{n} : n \in \mathbb{N}, n\geq 1 \} \cup ]1,2] \] M closed, compact or bounded is (proof) ?

OpenStudy (experimentx):

the set is bounded n=1 and n->inf, [0, 1) U [1, 2]

OpenStudy (experimentx):

the set is neither closed nor open. since you have [0, 1)

OpenStudy (experimentx):

I'm not sure about compactness ...

OpenStudy (anonymous):

thank you experimentX

OpenStudy (experimentx):

i tried my best.

OpenStudy (anonymous):

its good i think.. can you explain why we got \[[0,1)\] ?

OpenStudy (experimentx):

put n=1, you will get 0 put n-> infinity, you will get 0) ... since you can't put n=infinity directly.

OpenStudy (anonymous):

A compact set is closed and bounded. Since it is not closed, then it is not compact.

OpenStudy (anonymous):

It is not closed since \[ \lim_{n\to \infty}\frac{n-1}{n}=1 \]and 1 is not in the set.

OpenStudy (anonymous):

thank you very much mr Saab

OpenStudy (anonymous):

Mr @eliassaab when normaly a set closed and bounded, can you give me pls an example, so that i can understand it ?

OpenStudy (anonymous):

Like [0,1] is closed and bounded so it is compact.

OpenStudy (anonymous):

ok thank you

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