A gardener pushes down a handle applying a force of 250 N. The handle is inclined at 45 degrees to the horizontal. If the coefficient of kinetic friction between the wheels and the grass is 0.40, what is the acceleration of the 20kg lawnmower?

-- I just need to know the steps you have to do to get the answer. I don't need you to plug in the numbers.

Question

A gardener pushes down a handle applying a force of 250 N. The handle is inclined at 45 degrees to the horizontal. If the coefficient of kinetic friction between the wheels and the grass is 0.40, what is the acceleration of the 20kg lawnmower? 

--> I just need to know the steps you have to do to get the answer. I don't need you to plug in the numbers.

anonymous · Answer

Do you think this problem ignores rotational movement of tires?

anonymous · Answer

I'm guessing that's just summed up into the coefficient of the kinetic friction. It truly ignores the rotational movement, yes, but that's not our focus.

anonymous · Answer

F cos45 - U(mg + F sin45) = ma

anonymous · Answer

What is U in this case?

anonymous · Answer

coefficient of kinetic friction

anonymous · Answer

U = 0.40,

anonymous · Answer

@imron07  this...doesnt deal with rotational motin

anonymous · Answer

Lemme try that, I'm guessing all the steps I did are summed up into one equation :P

anonymous · Answer

Did u get the answer..)

anonymous · Answer

I got the answer right :) 
And if i were to do this without this superb equation, would the force be considered negative. (250N)