Question

find the slope of the line perpendicular to the line whose equation is given by 4y-9x=7. then find the equation of line passing through (3,4)

Answer 1

1. solve 4y-9x=7 for y
2. take the number beside x (coefficient) and writes its negative reciprocal
for example negative reciprocal of 1/2 is -2/1 because its flipped upside
down and the sign is changes
3. Then with you new slope (Which is the slope of your new line) put it in point slope for
which is y-(the y in the point) = Slope (x - (x in the point))
4. Solve for y and TA DA! you have the equation of your new line

Answer 2

@TAKEBACKMATH it looks cool verbal explanation but could you please explain mathematically :)

Answer 3

@cwrw238

Answer 4

@ParthKohli @Mikael

Answer 5

@everyone please

Answer 6

@hartnn

Answer 7

the slope of the given line can be found by comparing it with y=mx+c.
4y-9x=7
so 4y=9x+7
y= 9/4 x + 7/4
slope = 9/4
product of slopes of perpendicular lines = -1
so slope of required line will be -4/9.
so u have y= (-4/9)x+c
put, (x,y)=(3,4) here and find c.
can u?

Answer 8

wait

Answer 9

4=(-4/9)*3+C ...on solving i get C= 16? right?

Answer 10

??@hartnn

Answer 11

thanks :)

Answer 12

no!

Answer 13

what??

Answer 14

its c=16/3 :P
check again.

Answer 15

when u multiply 3 ,it gets multiplied with c also!

Answer 16

so finally, your equation will be
y=(-4/9)x+16/3
or
9y+4x=48.

Answer 17

\[4=\frac{ -4 }{ 9 }*3+C..... 4=\frac{ -4 }{ 3 }+C\] oh am so stupid....sorry @hartnn thanks a lot

Answer 18

welcome again :)