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Find the domain f(x)=square root of x+2
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\[\sqrt{x+2}\] find the domain
[-2, infinity]
how you have got it ?
so why is this ? please --- explain please for understanding
Square root functions domains cannot be negative, so all you have to do to solve this is find where x+2 is positive. x+2 is positive as long as x is greater than or equal to -2.
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Another one \[\sqrt{x-3}\div x-6\]
because of the x-6 in the denominator, the function will be undefined @x=6. Other than that its just like the previous one, so the domain would be [3,6) or (6, infinity)
and*
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