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Mathematics 20 Online
OpenStudy (anonymous):

Find the domain f(x)=square root of x+2

OpenStudy (anonymous):

\[\sqrt{x+2}\] find the domain

OpenStudy (anonymous):

[-2, infinity]

jhonyy9 (jhonyy9):

how you have got it ?

jhonyy9 (jhonyy9):

so why is this ? please --- explain please for understanding

OpenStudy (anonymous):

Square root functions domains cannot be negative, so all you have to do to solve this is find where x+2 is positive. x+2 is positive as long as x is greater than or equal to -2.

OpenStudy (anonymous):

Another one \[\sqrt{x-3}\div x-6\]

OpenStudy (anonymous):

because of the x-6 in the denominator, the function will be undefined @x=6. Other than that its just like the previous one, so the domain would be [3,6) or (6, infinity)

OpenStudy (anonymous):

and*

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