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Chemistry 21 Online
OpenStudy (anonymous):

A mixture is made of 3.35 g of SiO2, 0.38 g of cellulose and 8.76 g of calcium carbonate. What is the percent cellulose in the sample? and can you show how this is done i was confused

OpenStudy (anonymous):

.38/(3.35+.38+8.76) * 100= 3.04%

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