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Chemistry 23 Online
OpenStudy (anonymous):

what volume(ml)0.25M sodium iodine solution can be prepared from 0.50g of sodium iodine?

OpenStudy (anonymous):

(.50g)(1mol/150g) = .0033moles/(.25moles/L)=.0132L*(1000ML/1L)= 13.2mL

OpenStudy (anonymous):

thank you! :)

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