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Mathematics 13 Online
OpenStudy (anonymous):

Picture inside, but how does one prove an integral to be true without computing.

OpenStudy (anonymous):

OpenStudy (anonymous):

think about it what is the maximum value of cosx ?

OpenStudy (anonymous):

1

OpenStudy (anonymous):

good so in fact integral of x^2cos(x) <= x^2

OpenStudy (anonymous):

do you understand ?

OpenStudy (anonymous):

no, I'm suppose to prove the integral is equal to \[\frac{ 1 }{ 3 }\]

OpenStudy (anonymous):

wouldn't that equal to 1?

OpenStudy (anonymous):

that is right.. but if you understand that integral of x^2cos(x) <= integral of x^2 the answer is trivial since integral of x^2 is x^3 / 3 substituting the limits will give you 1/3

OpenStudy (anonymous):

integral of x^2cos(x) <= integral of x^2 this statement is true since cos(x) <= 1

OpenStudy (anonymous):

but the integral of x^2cos(x) would be x^3/3 -sin(x)

OpenStudy (anonymous):

they dont want you to evaluate x^2cos(x) they want you to bound it by an upper limit

OpenStudy (anonymous):

and since x^2cos(x) <= x^2 we get what they want

OpenStudy (anonymous):

do you understand what i mean ?

OpenStudy (anonymous):

@Coolsector I'm trying to, sorry for taking awhile, I'm trying to reread it until I do

OpenStudy (anonymous):

you managed to do it ?

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