Picture inside, but how does one prove an integral to be true without computing.
think about it what is the maximum value of cosx ?
1
good so in fact integral of x^2cos(x) <= x^2
do you understand ?
no, I'm suppose to prove the integral is equal to \[\frac{ 1 }{ 3 }\]
wouldn't that equal to 1?
that is right.. but if you understand that integral of x^2cos(x) <= integral of x^2 the answer is trivial since integral of x^2 is x^3 / 3 substituting the limits will give you 1/3
integral of x^2cos(x) <= integral of x^2 this statement is true since cos(x) <= 1
but the integral of x^2cos(x) would be x^3/3 -sin(x)
they dont want you to evaluate x^2cos(x) they want you to bound it by an upper limit
and since x^2cos(x) <= x^2 we get what they want
do you understand what i mean ?
@Coolsector I'm trying to, sorry for taking awhile, I'm trying to reread it until I do
you managed to do it ?
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