Question

am i doing this right?√-112 = 4√7

Answer 1

is that a minus sign within the square root?

Answer 2

i.e., is it \(\sqrt{-112}\)

Answer 3

yes

Answer 4

then your answer needs to include \(i=\sqrt{-1}\)

Answer 5

i.e. it is a complex number

Answer 6

yes and it has to be in i terms

Answer 7

e.g.: \(\sqrt{-8}=2\sqrt{2}i\)
note that the \(i\) is outside the square root symbol

Answer 8

then how do i do this one

Answer 9

you cn also write it as: \(2i\sqrt{2}\)

Answer 10

you have the right answer - you are just missing the 'i'.

Answer 11

then do you just multipy it with the i to make it positive

Answer 12

"make it positive" ?

Answer 13

well it is a negative number -112 so i put the i then √ to make it positive. I thought that ment i didnt need to use the i again

Answer 14

look at it this way:\[\sqrt{112}=4\sqrt{7}\]therefore:\[\sqrt{-112}\ne4\sqrt{7}\]otherwise you are saying that:\[\sqrt{112}=\sqrt{-112}\]

Answer 15

'i' is just a placeholder for \(\sqrt{-1}\)

Answer 16

so, for example:\[\sqrt{-4}=\sqrt{4}\times\sqrt{-1}=\sqrt{4}\times i=2i\]

Answer 17

oic so would it be 4 √7i

Answer 18

yes - although I would probably write it as: \(4i\sqrt{7}\)

Answer 19

to make it clear that the i is not under the square root symbol

Answer 20

oh so √-112 = 4i√7

Answer 21

thats is correct.

Answer 22

thank you

Answer 23

yw :)