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CALCULUS HELP (not enough members on on the Calc page right now... d/dx Integral from 10 to x^3 of 1/(p^2) dp Will show formatted equation in comments.
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\[d/dx \int\limits_{10}^{x^3} 1/(p^2) dp\]
use FTC
I know it's the 2nd ftc but I don't know how to plug in the limits. Do I need to derive x^3 when I bring it down?
and if you choose to integrate use subsitution say p^2= k, find dp /dk, complete the integration and thend find d/dx BUT best soln is use property of antiderivatives
oh ok i got it, so the lower limit of 10 becomes irrelevant, and the answer is just f(x), but you have to chain rule it so include the derivative of x^3. So it should be: \[3x^2 / x^6\]
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