Question

The space shuttle undergoes an acceleration of 53.9m/s2. How fast is it traveling at the end of 55.2s

Answer 1

You can't solve this problem without another variable. You must have either displacement or initial velocity in order to make any useful calculations.

Answer 2

Well I'm assuming initial velocity is O like from the rest

Answer 3

Okay, then this is simple. Use the formula: \[v_{f}=v_{i}+at\] where vf is your final velocity, vi is your initial velocity, a is acceleration, and t is time. Plug in your values and evaluate for vf.

Answer 4

Okay but m/s2 times s wouldn't it equal like s3

Answer 5

No; when you multiply \[m/s ^{2}\] by s, the s cancels out one of the s's on the bottom so you are left with m/s, the correct unit for velocity.

Answer 6

Nvm it cancels out, I get it

Answer 7

So did you get a final answer? Any more questions?

Answer 8

Yup.... I got it before but the s2 times s confused me

Answer 9

Good, then :)

Answer 10

Btw this one. You are in an elevator that is accelerating u upward at 4.55m/s2. How much time does it take you to reach a speed of 11m/s?

Answer 11

Again, you must have either the displacement or the initial velocity in order to solve. You have to specify what it is, because you can't always assume the object is at rest (initial velocity = 0).

Answer 12

I got like .41s

Answer 13

Assuming initial is at rest, cause they don't give it

Answer 14

Then you would simply plug the values into the equation from before with vf, vi, a, and t, and then evaluate for t.