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OpenStudy (anonymous):
1. Which of the following is a factor of x^2 – 6x – 27?
a. x + 3
b. x + 9
c. x – 1
d. None of the above
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OpenStudy (across):
Have you tried synthetic division?
OpenStudy (jiteshmeghwal9):
use the identity:-\[x^2-(a+b)x+ab\]
OpenStudy (anonymous):
@across, no.
OpenStudy (anonymous):
I would use REMAINDER THEOREM
OpenStudy (anonymous):
Do u know it? @bombshellbri
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OpenStudy (anonymous):
never learned that...
OpenStudy (anonymous):
substitute the given factors ....
OpenStudy (anonymous):
Actually Factor Theorem
OpenStudy (anonymous):
If polynomial f(x) is divided by (x-a) then (x-a) is said to be a factor of polynomial f(x) if f(a)=0
OpenStudy (anonymous):
got it?
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OpenStudy (anonymous):
not really.
OpenStudy (anonymous):
Here: f(x)=x^2-6x-27
OpenStudy (anonymous):
no i mean to say that
suppose to test x-a
substitute x=a in the given polynomial and if reduces to zero then x-a is its factor
OpenStudy (anonymous):
@sauravshakya , so where f(x) is, i should substitute the given choices to replace x?
OpenStudy (anonymous):
(x-a) ===> (x+3)
a=-3
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OpenStudy (anonymous):
example to for x^2-6x-27
testing x+3
let x+3=0 then x=-3
substitute that -3^2-6*(-3)-27
it gives 0 hence its a factor
OpenStudy (anonymous):
Now, find f(a)
OpenStudy (anonymous):
x + 3 is a factor
OpenStudy (anonymous):
Yep
OpenStudy (anonymous):
so this is the answer. correct?
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OpenStudy (anonymous):
Yes very correct
OpenStudy (anonymous):
thanks for your help
OpenStudy (anonymous):
Welcome
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