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Chemistry 19 Online
OpenStudy (anonymous):

How to write the reaction for this titration process ( cant figure it out) I started out with borax which i diluted 2x with in a 100ml volumetric flask. I then titrated it with HCL, what would you guys do as a reaction for it?

OpenStudy (anonymous):

well as dilution is not a chemical reaction you just write borax + HCl -> ......

OpenStudy (anonymous):

Well it starts off as Na2b407(aq) +2 hcl +5 h20 (l) ---> 4h3BO3(aq) +2NaCl(aq) to a complete ionic that gives me all of those ions breaking down (except for water) and I don't know which one to keep / take out

OpenStudy (anonymous):

well why would you take out anything, you write down the reaction and then it doesnt matter that it becomes ionized...

OpenStudy (anonymous):

Well I need to get the Net ionic equation, but I don't know whether I keep the Sodium, Oxygen, etc... Even in the product , which product do I keep in my net equation? The Hydrogen borate? or the salt? Thats where I get confuse

OpenStudy (anonymous):

ok so you keep it all... just be careful, did you have anhydrous borax or pentahydrate or decahydrate... it would go something like this for decahydrate: Na2B4O7·10H2O + 2 HCl → 4 H3BO3 + 2 NaCl + 5 H2O

OpenStudy (anonymous):

I believe I had pentahydrate, as I had 5 mole of hydrogen. but my net ionic would not use the whole reaction, I mean as im using titration im only looking at the base ( borax) + hcl + h20 . I see my answer but I just don't understand it. It says b407 + 2h(hydronium) + 5h20 ---> 4h3b03. I have to explain why we end up with b407 and 2hydronium too instead of Hcl Sorry this answer extrapolated to more :/

OpenStudy (anonymous):

ok no problem, now i understand your problem, well you have B4O7(2-) because borax is an ionic compound (salt) which by dissolving becomes ionized and that is why you have ion and H+ because HCl also dissolves and becomes ionized... get it now?

OpenStudy (anonymous):

wait why wouldnt you keep the whole borax compound with sodium though? and when you titrate you need to end up with a salt so why dont i keep the Sodium and Chlorine to give me NaCl in the net?

OpenStudy (anonymous):

well i would keep them thats what i tried to say... but then you asked to explain why are they in ionized form so i answered... :)

OpenStudy (anonymous):

No I understood that and thank you! but my net ionic ( the answer im supposed to get) is B407(2-) (aq) + 2h(+) + water ---> hydrogen borate :/ I understand how to do net ionic with precipitate but not with a whole aqueous reaction

OpenStudy (anonymous):

you got me confused now... Na2B4O7 -> 2Na+ + B4O7- HCl -> H+ + Cl- and now you have reaction with B4O7- and H+

OpenStudy (anonymous):

Yes thats why im confuse too haha. It goes like this molecular: Na2b407(aq) +2 hcl +5 h20 (l) ---> 4h3BO3(aq) +2NaCl(aq) to complete ioniic: 2Na(+) (aq) + 4b (3-)(aq) + 7O(6-) (aq) + 2H(+) (aq) + 2Cl (-)(aq) + 5 H2O(L) ---> 12H(+)(aq)+4B(3-)+12O(6-)(aq) + 2Na(+)(aq) + 2Cl(-)(aq) to net ionic which Im having trouble to get :/ (well i have the answer but I dopnt understand how my teacher got there)

OpenStudy (anonymous):

well teacher just took the B4O7 ion and paired it with H+ iond and water to get it solved

OpenStudy (anonymous):

is there a reason why the sodium wasn't used?

OpenStudy (anonymous):

sodium wasnt used cause she wrote dissolved or ionized form of borax and acid

OpenStudy (anonymous):

AAAAhhhhhh!! but then does it make the B407 a base solution to titrate with the hydronium ion ? and is the 4 hydrogen borate neutral ? O.O I mean if that is what the titration leads to, it must be a neutral compound?

OpenStudy (anonymous):

And btw if I have Borax pentahydrate, do I calculat ethe pentahydrate in the molecular weight>?

OpenStudy (anonymous):

yes if you have pentahydrate you must use weight of water in molecular weight of borax

OpenStudy (anonymous):

why would you think the solution is neutral after titration?!

OpenStudy (anonymous):

Because you always titrate an acid with a base or vice and vera and when I use penthalyphelin ( or whatever you werite it) the colour it reaches indicates a pH of almost 7 ( under or above but very close)

OpenStudy (anonymous):

ok lets just say it is pH 7 and borax has pH of 9,2 do you have any other questions cause i have to go

OpenStudy (anonymous):

No thats all thank you :) Have a good day

OpenStudy (anonymous):

not a problem and good luck

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