Mathematics
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OpenStudy (anonymous):
Simplify i23? help please!
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OpenStudy (anonymous):
i^23
OpenStudy (anonymous):
|dw:1347900084594:dw| @ksaichandra it looks like this
hartnn (hartnn):
u know what is 'i' ?
OpenStudy (anonymous):
do you mean i(23)
OpenStudy (anonymous):
oh i get it now but what is the meaning of the I
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hartnn (hartnn):
@Kristy143SIO do u know the value of i ?
OpenStudy (anonymous):
i Stands for the square root of negative one i believe @hartnn @FweaBoyLive
hartnn (hartnn):
that is correct.
so what is i^2 ?
OpenStudy (anonymous):
so i=-^23?
hartnn (hartnn):
\(\huge i=\sqrt{-1}\)
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OpenStudy (anonymous):
@hartnn could it be a multiplication or division
OpenStudy (anonymous):
if its multiplication its just plain simnple and if it is division it has to be a decimal
hartnn (hartnn):
@Kristy143SIO what is i^2 and i^3
u know ?
OpenStudy (anonymous):
@hartnn I have no clue?
hartnn (hartnn):
ok, since \(\huge i=\sqrt {-1}, i^2 =-1, i^3=i.i^2=-i\\ \huge i^4=1\)
did u get all these ???
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OpenStudy (anonymous):
huh? @hartnn
hartnn (hartnn):
u knew i=sqrt{-1} isn't it ?
so what do u get after squaring ?
i^2 = ?
OpenStudy (anonymous):
-2? @hartnn
hartnn (hartnn):
no its not -2
\(i^2=\sqrt{-1}^2=-1\)
ok ??
OpenStudy (anonymous):
ok thanks! gotcha! @hartnn
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hartnn (hartnn):
so now could u find, i^3, i^4,..... ?
OpenStudy (anonymous):
they would both be -1? @hartnn
hartnn (hartnn):
nopes, see my previous comment, i have given their values..