Question

Solve the system of equations using matrices. Use Gauss-Jordan elimination
3x-7y-7z = 7
6x+4y-3z=67
-6x-3y+z=-62

Answer 1

Hint:\[\begin{bmatrix}
3 & -7 & -7\\
6 & 4 & -3\\
-6 & -3 & 1
\end{bmatrix}\begin{bmatrix}
x\\
y\\
z
\end{bmatrix}=\begin{bmatrix}
7\\
67\\
-62
\end{bmatrix}.\]

Answer 2

so does x = 7

Answer 3

hmm

Answer 4

did you use Michael Jordan Elimination method to arrive at x=7?

Answer 5

the book I am using is really confusing it says I have to get 1 on top but I don't know how

Answer 6

http://ceee.rice.edu/Books/CS/chapter2/linear44.html

Answer 7

I see how to do it when the number is 0 or 1 but I don't know how to start with the 3

Answer 8

@across almost gave you the cramers rule

use it to find values of x, y, and z

Answer 9

http://www.karlscalculus.org/cgi-bin/linear.pl

Answer 10

okay I used that but my answers I think are what is confusing me these are my choices
a. {(7,1,7)}
b. {14,7,-7)}
c. {(-7,7,14)}
d. {(7,7,1)}

Answer 11

If you have choices, all you have to do is substitute, I mean, slam-dunk them and check!

Answer 12

I did that and none of them equal up

Answer 13

that is the way they are

Answer 14

I'm interested in knowing that this Michael Jordan method is