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f(t)=(√4)/(t^3) find f′(t):
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f'(t)= sqrt(4) 3t^2
i dont think ther is way to guide this...only one can post f'(t)
this is in the form 2t^(-3), derivating is (-3)2t^(-4)=-6/t^4
@akash809 it a division not a multiplication
ohhh...sorry just misread it...
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where did u get this? "2t^(-3)"
the 2? from the sqrt(4)?
yep, and the -3 because t^(-n)=1/t^n
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