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Mathematics 14 Online
OpenStudy (anonymous):

Prove |x| ≥ x

OpenStudy (anonymous):

bcoz if x>=0 then x>=x and if x<0 then |x|>x hence |x|>x for all x in R

OpenStudy (anonymous):

\[|x| \ge x\]\[(x)^{2} \ge x\]\[x ^{2}-x \ge 0\]\[x (x-1) \ge 0\]\[x \ge 0\]\[x = 1\]

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