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Mathematics 16 Online
OpenStudy (anonymous):

I could really use some help with an algebra travel/distance problem. Bill and Tom are having a bicycle race, each going to the other's house. Tom follows the straight lines, going 21 mph (for a total of 33 miles, and Bill takes the hypotenuse of the triangle as a shortcut, going 15 mph (for 15 miles) and then 21 mph the rest of the way (12 miles). I need to figure out how long it too each of them to get to the other's house.

OpenStudy (anonymous):

OpenStudy (anonymous):

How long does it take to reach 21 miles if you're going 21 MLES PER HOUR?

OpenStudy (anonymous):

That's obvious. I need help with the other one to double check my answer.

OpenStudy (anonymous):

Well first off, Bill has 33 miles to do...?

OpenStudy (anonymous):

Tom has to do 24+9=33 miles

OpenStudy (anonymous):

Ok! So if you just want to check your asnwers, I can just give them to you.

OpenStudy (anonymous):

Bill has 15 miles at 15 mph, and then 12 miles at 21 mph. I understand how to get to the answer, but I need to show my work and I want to make sure I am showing all steps.

OpenStudy (anonymous):

I see,

OpenStudy (anonymous):

That would be great!

OpenStudy (anonymous):

Let's start with Tom. 21 mph for 33 miles 33./21 x 60 = 1h34 approx. Bill : 15mph for the first 15 miles so 1 hour for that. 21mph for 12 miles 12/21 x 60 =34 minutes approx. 1h + 34 =1h34 approx. It took 1h34 to get to one house to another. I have to go, sorry if I skiiped a few steps.

OpenStudy (anonymous):

thanks so much, thats what i got too!

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