Question

log 5^64-log 5^ (8/3)+ log5 ^ 2=log5^4p

Answer 1

the easiest way to solve this problem is to use the log laws for powers

\[\log (x^a) = a \log (x)\]

so you will have

\[64 \log 5 - \frac{8}{3} \log 5 + 2 \log 5 = 4p \log 5\]

divide log 5 as a common factor and then solve for p

Answer 2

the answer i got for it was 12.

Answer 3

66 - 8/3 = 4p

so p = 16 1/2 - 2/3

looks like 15 and a bit to me