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OpenStudy (anonymous):
If a gas has a volume of 1 L at a pressure of 270 kPa, what volume will it have when the pressure is increased to 540 kPa? Assume the temperature and number of particles are constant. Show your work.
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OpenStudy (anonymous):
apply boyle's law p1v1=p2v2 here p1=270kpa v1=1L p2=540kpa solve for v2 you'll get the answer
OpenStudy (anonymous):
do you know it cuz i think i might know it is it V = PV P = 270 V = 1 P = 540 V = PV/P V = (270 x 1)/540 = 0.5L
OpenStudy (anonymous):
is this right
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