If a gas has a volume of 1 L at a pressure of 270 kPa, what volume will it have when the pressure is increased to 540 kPa? Assume the temperature and number of particles are constant. Show your work.

Question

anonymous · Answer

apply boyle's law p1v1=p2v2
here p1=270kpa v1=1L 
p2=540kpa
solve for v2 you'll get the answer

anonymous · Answer

do you know it cuz i think i might know it is it V = PV
 P = 270
 V = 1
 P = 540
 V = PV/P
 V = (270 x 1)/540
 = 0.5L

anonymous · Answer

is this right