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Mathematics 24 Online
OpenStudy (anonymous):

Choose the correct description of the graph of the compound inequality x - 3 < -9 or x + 5=>10 A. A number line with an open circle on -6, shading to the left, and a closed circle on 5, shading to the right. B. A number line with a closed circle on -6, shading to the left, and an open circle on 5, shading to the right. C. A number line with an open circle on -6, a closed circle on 5, and shading in between. D. A number line with a closed circle on -6, an open circle on 5, and shading in between.

OpenStudy (kymber):

First you need to solve for x in both equations, can you do that?

OpenStudy (anonymous):

x<-6 or x=>5?

jimthompson5910 (jim_thompson5910):

the => should be >=, but yes it's x<-6 or x>=5

jimthompson5910 (jim_thompson5910):

now graph these two

OpenStudy (anonymous):

so its C

jimthompson5910 (jim_thompson5910):

why C?

OpenStudy (anonymous):

because its an opened circle on -6 since the inequality sign is < not =< and a cosed circle on -5 since the inequality sign is >= not >

OpenStudy (anonymous):

closed*

jimthompson5910 (jim_thompson5910):

you have the open/closed circle portions right, but what about the shading directions

jimthompson5910 (jim_thompson5910):

double check which way you're supposed to shade

OpenStudy (anonymous):

and shading in between because both signs x is greater than or equal to 5 but less than 6

jimthompson5910 (jim_thompson5910):

it's x<-6 and not x<6

OpenStudy (anonymous):

sorry x is less than -6

jimthompson5910 (jim_thompson5910):

So is it possible to be BOTH less than -6 AND greater than 5 (or equal to 5) at the same time?

OpenStudy (anonymous):

no so then the signs would have to flip and make it x>-6 or x=<5

jimthompson5910 (jim_thompson5910):

yes, but that's not the case here

jimthompson5910 (jim_thompson5910):

so shading in between is impossible

OpenStudy (anonymous):

So then the answer is A

jimthompson5910 (jim_thompson5910):

you got it

OpenStudy (anonymous):

thanks man

jimthompson5910 (jim_thompson5910):

np

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