This is not a math question, but a chemistry question, no one is answering in the chemistry section so I figured I'd ask my question here. An element has three naturally occurring isotopes. Use the information below to calculate the weighted average atomic mass of the element, showing both the setup and the final answer for the calculation.
okay, I multiplied the atomic mass by the abundance but I now the answer I got is incorrect, can someone please help explain to me how this works?
know*
ill do the math, give me a sec
ok hw much did u get.. . i think we need to multiply and take average
scratch that. average is not needed. just myltiplying is enough
15.99(0.99762)+16.99)0.00038)+17.99(0.002) = 16.5697002
thats what I got
16.99(0.00038)*
time to burn ur calculator
first, I converted my percentages to decimals and plugged in the numbers
wolfram says 15.99438 http://www.wolframalpha.com/input/?i=%2815.99*%2899.762%2F100%29+%2B+16.99*%28.038%2F100%29+%2B+17.99*%28.2%2F100%29+%29
do u know what I did wrong on mine?
1 sec
okay
calculate it again
conversion looks okay to me, while adding something went wrong i guess
okay, im gonna try doing it again, hold on
15.99(0.99762)+16.99(0.00038)+17.99(0.002) \(\huge \ne \) 16.5697002
okay, I got the right one, I must have made a mistake in my calculator the first time, its 15.99438 :)
awesome ! :)
but would I write it like that or would I have to round to get a smaller answer?
and I have to put a unit behind it right?
or does it just stay like that?
would I have to put the u behind it or something?
i think so.. . since all masses are rounded to hundreth in the input, you may round the answer as well... an d yes unit is "u"
okay so i could put this as 16.0 u?
u rounded too much ;)
or too much, okay..
round it to hundreth 15.99438 ~ 15.99
then I could do 15.99
haha, yeah! :)
looks good :) 15.99 u
okay thanks again so much, you have been an enormous help! :)
np :)
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