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Mathematics 15 Online
OpenStudy (anonymous):

This is not a math question, but a chemistry question, no one is answering in the chemistry section so I figured I'd ask my question here. An element has three naturally occurring isotopes. Use the information below to calculate the weighted average atomic mass of the element, showing both the setup and the final answer for the calculation.

OpenStudy (anonymous):

OpenStudy (anonymous):

okay, I multiplied the atomic mass by the abundance but I now the answer I got is incorrect, can someone please help explain to me how this works?

OpenStudy (anonymous):

know*

OpenStudy (anonymous):

ill do the math, give me a sec

ganeshie8 (ganeshie8):

ok hw much did u get.. . i think we need to multiply and take average

ganeshie8 (ganeshie8):

scratch that. average is not needed. just myltiplying is enough

OpenStudy (anonymous):

15.99(0.99762)+16.99)0.00038)+17.99(0.002) = 16.5697002

OpenStudy (anonymous):

thats what I got

OpenStudy (anonymous):

16.99(0.00038)*

ganeshie8 (ganeshie8):

time to burn ur calculator

OpenStudy (anonymous):

first, I converted my percentages to decimals and plugged in the numbers

OpenStudy (anonymous):

do u know what I did wrong on mine?

ganeshie8 (ganeshie8):

1 sec

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

calculate it again

ganeshie8 (ganeshie8):

conversion looks okay to me, while adding something went wrong i guess

OpenStudy (anonymous):

okay, im gonna try doing it again, hold on

ganeshie8 (ganeshie8):

15.99(0.99762)+16.99(0.00038)+17.99(0.002) \(\huge \ne \) 16.5697002

OpenStudy (anonymous):

okay, I got the right one, I must have made a mistake in my calculator the first time, its 15.99438 :)

ganeshie8 (ganeshie8):

awesome ! :)

OpenStudy (anonymous):

but would I write it like that or would I have to round to get a smaller answer?

OpenStudy (anonymous):

and I have to put a unit behind it right?

OpenStudy (anonymous):

or does it just stay like that?

OpenStudy (anonymous):

would I have to put the u behind it or something?

ganeshie8 (ganeshie8):

i think so.. . since all masses are rounded to hundreth in the input, you may round the answer as well... an d yes unit is "u"

OpenStudy (anonymous):

okay so i could put this as 16.0 u?

ganeshie8 (ganeshie8):

u rounded too much ;)

OpenStudy (anonymous):

or too much, okay..

ganeshie8 (ganeshie8):

round it to hundreth 15.99438 ~ 15.99

OpenStudy (anonymous):

then I could do 15.99

OpenStudy (anonymous):

haha, yeah! :)

ganeshie8 (ganeshie8):

looks good :) 15.99 u

OpenStudy (anonymous):

okay thanks again so much, you have been an enormous help! :)

ganeshie8 (ganeshie8):

np :)

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