In the morning, Alan drove 100 miles at the rate of
60 miles per hour; in the afternoon, he drove
another 100 miles at the rate of 40 miles
per hour. What was his average rate of speed,
in miles per hour, for the day?
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OpenStudy (anonymous):
k...
OpenStudy (anonymous):
d=100
OpenStudy (anonymous):
anything?
OpenStudy (anonymous):
ahh
OpenStudy (anonymous):
60+40/2=50
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OpenStudy (anonymous):
derp
OpenStudy (anonymous):
C.
OpenStudy (anonymous):
no
OpenStudy (anonymous):
B.
OpenStudy (anonymous):
48
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OpenStudy (anonymous):
nope
OpenStudy (anonymous):
that'swrong
OpenStudy (anonymous):
it's 48
OpenStudy (anonymous):
heck no
OpenStudy (anonymous):
oh i mean heck no to 50
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OpenStudy (anonymous):
average speed is not the average of the speeds
OpenStudy (anonymous):
oh man, you are a guru
OpenStudy (anonymous):
you are even higher than DA PANIC!!!!!!
OpenStudy (anonymous):
Oh, sorry...just been a while since I've done these...
OpenStudy (anonymous):
figure out how long it took to get there, then figure out how long it took to get back
that is the total time
divide the total distance (200 miles ) by the total time to get the average speed
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OpenStudy (anonymous):
2.5+1.666666667
OpenStudy (anonymous):
divided by 200
OpenStudy (anonymous):
equal 48
OpenStudy (anonymous):
that it?
OpenStudy (anonymous):
200/4.166666667?
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OpenStudy (anonymous):
=48
OpenStudy (anonymous):
100/60=5/3
OpenStudy (anonymous):
100/40=2.5
OpenStudy (anonymous):
time going it \(\frac{100}{60}\) time returning is \(\frac{100}{40}\) total time is
\[\frac{100}{60}+\frac{100}{40}=\frac{25}{6}\] and
\[200\div \frac{25}{6}=200\times \frac{6}{25}=8\times 6=48\] as luisz said
OpenStudy (anonymous):
5/2+5/3=15/6+10/6=25/6
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OpenStudy (anonymous):
200 divided by 25/6=48
OpenStudy (anonymous):
ty
OpenStudy (anonymous):
you nothing about truth tables, guru?
OpenStudy (anonymous):
now redo the problem replacing 100 by \(m\) and see that the answer is still 48 mph
OpenStudy (anonymous):
by friend, aripotta needs help with them?
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