Question

differentiate 9sec6x

do i have to use both product and chain rules?

Answer 1

yes!

Answer 2

somebody mind so it as well so i can see how its done? derivative of sec is secxtanx and thats messing me up

Answer 3

doing it as well*

Answer 4

convert the secx to 1/cosx, that should help. And secx.tanx =sinx

Answer 5

What is the function you wish to differentiate? \[\ \ \ \ 9\sec{x} * 6x\\ = 54x\sec{x}\tan{x} + 54\sec{x}\\ = 54\sec{x}\ [x\tan{x} + 1]\]

Answer 6

when i replaced sec6x with 1/cos6x, this is what i got as my final answer, still wrong though.

(0*1/cos6x)+(9+1/-sinx*6)

Answer 7

I guess you made a mistake in writing the post, it says secx6x, the function is sec6x???

Answer 8

oh wow, your right. my fault.

differentiate 9sec6x

Answer 9

use the chain rule only!

Answer 10

ah. so it was a chain rule only problem? or could it be done using both product and chain?

Answer 11

ugh. i just copied pasted your exact answer, says it was wrong. ._.

Answer 12

still keeps saying incorrect. >.<

Answer 13

I crossed check, the answer indeed is 54*sec6x*tan6x. Just see if the equation was properly written. I mean I wrote 54sec6x.tan6x, try using 54*sec(6x)*tan(6x).

hope that would work

Answer 14

yep, was written wrong, thank you for helping me these past 15-20 minutes!

Answer 15

^_^