can sombody solve this quadratic and explain it to me?? 3x^3-18X^2+24X=0

Question

anonymous · Answer

try factoring out 3x from all the terms

anonymous · Answer

and then plugging into the quadratic formula??

anonymous · Answer

nah, you don't really need the quadratic formula for this

anonymous · Answer

$$3x^3 - 18x^2 + 24x = 0\3x(x^2 - 6x + 8) = 0\3x(x-4)(x-2) = 0$$

anonymous · Answer

3x^3-18X^2+24X=0
3x( x^2 - 6x +8) = 0

anonymous · Answer

then you can factor further then stuff in the parenthesis

anonymous · Answer

I guess I should have mentioned that your solving to find x is that possible??

anonymous · Answer

since it was x^3 in the equation, there should be three x values as solutions, just like x^2 equations have two solutions

anonymous · Answer

@mewi2671 solving to find x for that equation? Simple. Any of those factors could be 0 to cause the entire function to be 0. So, try for each one. $$3x=0\x=0$$ $$x-4=0\x=4$$ $$x-2=0\x=2$$

anonymous · Answer

Thank you all very very much!!!!

anonymous · Answer

I like that approach... good stuff :)