Question

How do you solve a quadratic equation with x^3? Like -
x^3 + 2x^2 + 2x + 4 = 0

Answer 1

Factor x^3 + 2x^2 + 2x + 4

Answer 2

I can do x^2 + 4x + 4 to (x+2)(x+2).
But how with the extra x^3? Going back to school and been a long time...

Answer 3

x^3 + 2x^2 + 2x + 4
x^2(x+2)+2(x+2)
(x+2) (x^2+2)

Answer 4

Now, (x+2) (x^2+2) =0

Answer 5

Can u continue from here?

Answer 6

YES, THANKS!

Answer 7

This is not a quadratic equation; it is a cubic equation.

You got (x+2), that is a correct factor. If you know how to do polynomial division, you should be able to get an answer with only brackets. Do not care if the content inside have a degree higher than one. Why? Because it's the same catch - anything times anything is zero. Even if you have this equation: (x^4)(x^8) = 0, you can still solve this because when they multiply, they lead to zero.

Answer 8

WELCOME