Question

Solve:
^x-1=x-3

Answer 1

\[\sqrt{x-1}=x-3\]

Answer 2

@amistre64 can you help me

Answer 3

maybe, what is it you need help with?

Answer 4

I have been stuck on this problem as I know the answer is 5 but I get stuck here

Answer 5

did you start by squaring each side?

Answer 6

yes

Answer 7

x-1 = x^2 -6x + 9

subtract x and add 1 to each side to zero it out, then all thats left to do is solve the quadratic

Answer 8

thats what I get

Answer 9

0=x^2-7x+8

Answer 10

but I cant get passed here

Answer 11

try adding 1 instead of subtracting it

Answer 12

ugggg

Answer 13

what methods do you know for solving a quadratic?

Answer 14

what do you mean. I see my mistake now thank you

Answer 15

well, there a many methods taught that will solve a quadratic equation. Since we have a quadratic equation, I assume we can use some of them to help us out :)

Answer 16

x^2 -7x + 10 ; if this is has rational roots, this is one way we can find them

step 1, assume it factors

x^2 -7x + 10 = (x )(x )

step 2, notice the last sign, its positive so our fillins are same signs

step 3, notice the middle sign is negatice, the larger value is negative (and by default in this case both are negative)

x^2 -7x + 10 = (x - )(x - )

step 4, what are the factors of 10?

1,10
2, 5

step 5, which set adds up to 7? 2,5, fill them in

x^2 -7x + 10 = (x - 2)(x - 5)

step 6, what values of x makes this go zero?

(x - 2)(x - 5) = 0

Answer 17

one of the values you get will be extraneous, we actually created it when we squared the stuff at the start. so test out which value is actually "good" inthe setup