Help? A rectangular storage container with an open top is to have a volume of 18 cubic meters. The length of its base is twice the width. Material for the base costs 13 dollars per square meter. Material for the sides costs 7 dollars per square meter. Find the cost of materials for the cheapest such container.
I alread have w^3=378/52 which is 7.27 What should I do step by step next????
i think it's w^3=252/54 to match your answer?
hw did u get w^3 = 378/52 ?
could be wrong though
i'm rushing it's due in like 33 mins hehe
im aslo getting w^3 = 378/54,
when u let f'(w) = 0
yes that's right i just recheck it
so what do i need to do next?
find value 'w', and substitute in cost function ?
w = cuberoot(378/52)
yeah= 8.088453308456256
whats 8.088 ?
wolfram says cost is ~ 293 http://www.wolframalpha.com/input/?i=26*%281.937%29%5E2+%2B+378%2F%281.937%29
\[\text{The volume of a rectangular prism is as follows.}\\ \ \ \ V = lwh\\ \text{Given as follows.}\\ \ \ \ V = 18\\ \ \ \ l = 2w\\ \text{Derive for the area of the base and sides, respectively.}\\ \ \ \ A_1 = lw\\ \ \ \ A_2 = 2h(w + l)\\ \text{Let's try to reduce our volume equation.}\\ \ \ \ 18 = 2w^2h\\ \ \ \ h = 9w^{-2}\\ \text{Derive the cost function.}\\ \ \ \ C(w) = 13A1 + 7A2\\ \ \ \ \ \ \ \ \ \ \ \ = 13lw + 14h(w+l)\\ \ \ \ \ \ \ \ \ \ \ \ = 26w^2 + 42hw\\ \ \ \ \ \ \ \ \ \ \ \ = 26w^2 + 378w^{-1}\\ \text{Now, let's differentiate it for optimization.}\\ \ \ \ C'(w) = 52w - 378w^{-2}\\ \text{Let's determine the optimal width, }w^*.\\ \ \ \ C'(w*) = 52w^* - 378w^{*-2}\\ \ \ \ 0 = 52w^* - 378w^{*-2}\\ \ \ \ 378w^{*-2} = 52w^*\\ \ \ \ 378 = 52w^{*3}\\ \ \ \ w*^3 = \frac{378}{52}\\ \ \ \ w* = [\frac{378}{52}]^{\frac13}\\ \text{Now we know the optimal width, so let's calculate it's cost.}\\ \\C(w*) = 26[\frac{378}{52}]^\frac23 + 378[\frac{378}{52}]^{-\frac{1}3}\\ \ \ \ \ \ \ \ \ \ \ \simeq292.70 \]
thanks guys!!!
Who wants a medal? And who want me to be his fan?
lol you're my fan already n u gave me many medals before... :)
I think whoever wants to manually simplify the cost at the end deserves as many medals as possible... :-)
Oh K OB thanks ganeshie8! I'm ur fan in heart! :)
that word keeps me motivated me for next problem ;)
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