Question

for the function f(x)=(8-x^3)/(x^2-4)
evaluate the function the values of x compute 2.5

Answer 1

\[\large{f(x) = \frac{(8-x^3)}{(x^2-4)}}\]
\[\large{f(x) = \frac{(2^3-x^3)}{(x^2-2^2)}}\]
\[\large{f(x) =\frac{(2+x)(4+x^2-2x)}{(x-2)(x+2)}}\]

Answer 2

well factorise the numerator and demonimator 1st

the numerator is the difference of 2 cubes... the denominator is the difference of 2 square

Answer 3

Just like I did above :)