@hartnn I understand your explanation but I just don't get how (1/y)(dy/dt) becomes (d/dt)ln|y| . I understand how (d/dt)ln|y| becomes (1/y)(dy/dt) but not the other way around
OpenStudy (he66666):
@henpen Yes, I get it but how does (1/y)(dy/dt) become (d/dt)ln|y| ?
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OpenStudy (anonymous):
d(lny)/dy=1/y
OpenStudy (he66666):
Oh I see. So I guess you just substitute d(lny)/dy into 1/y then solve it?