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OpenStudy (anonymous):
Find the inverse of the function \[f(x)=\sqrt{x}+6\]
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OpenStudy (anonymous):
Rearrange so
x=f(x)/6
then invert
f^-1(x)=x/6
OpenStudy (bahrom7893):
Wrong
OpenStudy (bahrom7893):
replace f(x) by x and x by f(x) and solve for f(x)
OpenStudy (bahrom7893):
x=sqrt(f(x)) + 6
OpenStudy (bahrom7893):
Solve for f(x)
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OpenStudy (anonymous):
An inverse function in this case will be something that turns \[\sqrt{x}+6 \rightarrow x\]
OpenStudy (bahrom7893):
x-6=sqrt(f(x))
inverse is:
f^-1(x) = (x-6)^2
OpenStudy (anonymous):
In comparison to the normal function:\[x \rightarrow \sqrt{x}+6\]
OpenStudy (anonymous):
@bahrom7893 does this method work for finding all inverse functions?
OpenStudy (bahrom7893):
well i've always used it. Idk of any exceptions.
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OpenStudy (bahrom7893):
oh it does... but i showed u the steps in reverse...
OpenStudy (bahrom7893):
When you have an equation, solve for x. You'll get:
x = y+sqrt(y) or something.. <-- I made that up, so the inverse will be:
f^-1(x) = x+sqrt(x)
OpenStudy (anonymous):
your hella cool. thanks.
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OpenStudy (anonymous):
let y= sqrt(x)+6
4y-6=sqrt(x)
x=(4y-6)^2
replace x by inverse (x) and y by x,
therefore inverse(x)= (4x-6)^2
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