Question

Radical expression question

Answer 1

@jim_thompson5910 , help please ?

Answer 2

\[\Large \sqrt{6}\left(7\sqrt{3}+6\right)\]

Start off by distributing to get

\[\Large \sqrt{6}*7\sqrt{3}+\sqrt{6}*6\]

\[\Large 7\sqrt{6}*\sqrt{3}+6\sqrt{6}\]

What's next?

Answer 3

combining like terms ?

Answer 4

close, but what do you get when you simplify \[\Large \sqrt{6}*\sqrt{3}\] ??

Answer 5

√2

Answer 6

\[\Large \sqrt{6}*\sqrt{3}\]

\[\Large \sqrt{6*3}\]

\[\Large \sqrt{18}\]

so far so good?

Answer 7

So it's (sqrt) 18 instead of (sqrt) 2 ?

Answer 8

close, but we're not done yet

Answer 9

\[\Large \sqrt{18}\]

\[\Large \sqrt{9*2}\]

\[\Large \sqrt{9}*\sqrt{2}\]

\[\Large 3\sqrt{2}\]

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So \[\Large \sqrt{6}*\sqrt{3} = 3\sqrt{2}\]

Answer 10

\[\Large \sqrt{6}\left(7\sqrt{3}+6\right)\]

\[\Large \sqrt{6}*7\sqrt{3}+\sqrt{6}*6\]

\[\Large 7\sqrt{6}*\sqrt{3}+6\sqrt{6}\]

\[\Large 7*3\sqrt{2}+6\sqrt{6}\]

\[\Large 21\sqrt{2}+6\sqrt{6}\]

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So in the end,

\[\Large \sqrt{6}\left(7\sqrt{3}+6\right) = 21\sqrt{2}+6\sqrt{6}\]

Answer 11

I see.