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Find the quotient of - QuestionCove
OpenStudy (anonymous):

Find the quotient of

5 years ago
OpenStudy (anonymous):

5 years ago
OpenStudy (helder_edwin):

u can do this \[ \large \frac{A+B}{C}=\frac{A}{C}+\frac{B}{C} \] and then simplify each fraction separatedly

5 years ago
OpenStudy (anonymous):

i dont think so.. thats really complicated :/

5 years ago
OpenStudy (helder_edwin):

complicated?

5 years ago
OpenStudy (anonymous):

yeah...

5 years ago
OpenStudy (helder_edwin):

\[ \large \frac{-36x^3-6x^2+12x}{-6x}= \frac{-36x^3}{-6x}+\frac{-6x^2}{-6x}+\frac{12x}{-6x} \]

5 years ago
OpenStudy (helder_edwin):

now simplify.

5 years ago
OpenStudy (anonymous):

okay gimmie a sec :)

5 years ago
OpenStudy (anonymous):

6x + 1x^2 -2x

5 years ago
OpenStudy (helder_edwin):

u got the powers wrong.

5 years ago
OpenStudy (helder_edwin):

remember this \[ \large \frac{a^m}{a^n}=a^{m-n} \]

5 years ago
OpenStudy (anonymous):

okay. so 6x = 1x-2x^2

5 years ago
OpenStudy (helder_edwin):

no just check the powers, the coefficients are ok

5 years ago
OpenStudy (campbell_st):

factorise the numerator \[\frac{-6x(6x^2 + x - 2)}{-6x}\] cancel the common factor

5 years ago
OpenStudy (anonymous):

so its 6x^2 + x -2

5 years ago
OpenStudy (anonymous):

Then whats the next step. iidk how to do the exponents?

5 years ago
OpenStudy (helder_edwin):

that's it

5 years ago
OpenStudy (campbell_st):

thats it well done

5 years ago
OpenStudy (anonymous):

Oh wow! that's so simple! i didn't know it was that easy! Thank you guys

5 years ago
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